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2012 TYS
Question 4
Question

In the triangle $ABC$, $AB=1$, angle $BAC=\theta $ radians and angle $ABC=\frac{3}{4}\pi $ radians (see diagram).
- Show that $AC=\frac{1}{\cos \theta -\sin \theta }$.
[4]
- Given that $\theta $ is a sufficiently small angle, show that$AC\approx 1+a\,\theta +b\,{{\theta }^{2}}$,for constants $a$ and $b$ to be determined.
[4]