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2013 TYS
Question 2
Question
It is given that
$y=\frac{{{x}^{2}}+x+1}{x-1}$, $x\in \mathbb{R}$, $x\ne 1$.
Without using a calculator, find the set of values that $y$ can take.
[5]
It is given that
$y=\frac{{{x}^{2}}+x+1}{x-1}$, $x\in \mathbb{R}$, $x\ne 1$.
Without using a calculator, find the set of values that $y$ can take.
[5]